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MathJax support
JavaScriptを有効にしてください
MathJax support
📅 2019/11/16
·
📝 2021/9/11
·
☕ 1 分で読めます
🏷️
When
a
≠
0
, there are two solutions to
(
a
x
2
+
b
x
+
c
=
0
)
and they are
x
=
−
b
±
b
2
−
4
a
c
2
a
.
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